Cryptic Arithmetic TWO+TWO+TWO+SIX, VI+VI=VII

TWO+TWO+TWO+SIX
VI+VI=VII


VI+VI=XII
means I+I = I
only I=0 satisfies rule, no other choice
answer: 50+50=100
V=5
I=0
X=1


From VI+VI=XII
V=5,I=0,X=1
so TWO+TWO+TWO=SIX=S01
3xTWO=SIX => SIX is divisible by 3
Digital root of SIX is divisible by 3 => S+I+X is multiple of 3

Possible: 201, 501 or 801
201/3=67 or 067
501/3=167
801/3=267

T=0,1 or 2 but I=0 and X=1, so T=2
W=6
0=7

Solution:

267+267+267=801
50+50=100